4x^2-156x+1496=0

Solution for 4x^2-156x+1496=0 equation:

4x^2-156x+1496=0

a = 4; b = -156; c = +1496;
Δ = b2-4ac
Δ = -1562-4·4·1496
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-156)-20}{2*4}=\frac{136}{8}
=17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-156)+20}{2*4}=\frac{176}{8}
=22
$